Base | Representation |
---|---|
bin | 110010100001110011… |
… | …000110100011001111 |
3 | 12012001001201122110001 |
4 | 302201303012203033 |
5 | 1342103024314003 |
6 | 40531330225131 |
7 | 3630316354111 |
oct | 624163064317 |
9 | 165031648401 |
10 | 54254135503 |
11 | 21011055017 |
12 | a6217251a7 |
13 | 5168221279 |
14 | 28a97193b1 |
15 | 16280b961d |
hex | ca1cc68cf |
54254135503 has 2 divisors, whose sum is σ = 54254135504. Its totient is φ = 54254135502.
The previous prime is 54254135497. The next prime is 54254135531. The reversal of 54254135503 is 30553145245.
54254135503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54254135503 - 25 = 54254135471 is a prime.
It is a super-2 number, since 2×542541355032 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54254135203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27127067751 + 27127067752.
It is an arithmetic number, because the mean of its divisors is an integer number (27127067752).
Almost surely, 254254135503 is an apocalyptic number.
54254135503 is a deficient number, since it is larger than the sum of its proper divisors (1).
54254135503 is an equidigital number, since it uses as much as digits as its factorization.
54254135503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180000, while the sum is 37.
The spelling of 54254135503 in words is "fifty-four billion, two hundred fifty-four million, one hundred thirty-five thousand, five hundred three".
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