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54303102149 = 531024586833
BaseRepresentation
bin110010100100101101…
…111001010011000101
312012011110212102001112
4302210231321103011
51342203043232044
640540235534405
73631452516032
oct624455712305
9165143772045
1054303102149
112103675a41a
12a635bba405
13517540720a
1428b2024389
15162c53d09e
hexca4b794c5

54303102149 has 4 divisors (see below), whose sum is σ = 55327689036. Its totient is φ = 53278515264.

The previous prime is 54303102137. The next prime is 54303102167. The reversal of 54303102149 is 94120130345.

54303102149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 18767082049 + 35536020100 = 136993^2 + 188510^2 .

It is a cyclic number.

It is not a de Polignac number, because 54303102149 - 212 = 54303098053 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54303102109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 512293364 + ... + 512293469.

It is an arithmetic number, because the mean of its divisors is an integer number (13831922259).

Almost surely, 254303102149 is an apocalyptic number.

It is an amenable number.

54303102149 is a deficient number, since it is larger than the sum of its proper divisors (1024586887).

54303102149 is a wasteful number, since it uses less digits than its factorization.

54303102149 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1024586886.

The product of its (nonzero) digits is 12960, while the sum is 32.

The spelling of 54303102149 in words is "fifty-four billion, three hundred three million, one hundred two thousand, one hundred forty-nine".

Divisors: 1 53 1024586833 54303102149