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543042540437 is a prime number
BaseRepresentation
bin1111110011011111101…
…10111001001110010101
31220220200120100022120212
413321233312321032111
532344122342243222
61053245330135205
754143046301415
oct7715766711625
91826616308525
10543042540437
1119a3373a2171
12892b3a21505
133c29365a807
141c3d790c645
15e1d47b36e2
hex7e6fdb9395

543042540437 has 2 divisors, whose sum is σ = 543042540438. Its totient is φ = 543042540436.

The previous prime is 543042540401. The next prime is 543042540463. The reversal of 543042540437 is 734045240345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 540505806481 + 2536733956 = 735191^2 + 50366^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-543042540437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 543042540394 and 543042540403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (543042740437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271521270218 + 271521270219.

It is an arithmetic number, because the mean of its divisors is an integer number (271521270219).

Almost surely, 2543042540437 is an apocalyptic number.

It is an amenable number.

543042540437 is a deficient number, since it is larger than the sum of its proper divisors (1).

543042540437 is an equidigital number, since it uses as much as digits as its factorization.

543042540437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 806400, while the sum is 41.

The spelling of 543042540437 in words is "five hundred forty-three billion, forty-two million, five hundred forty thousand, four hundred thirty-seven".