543120433 has 2 divisors, whose sum is σ = 543120434. Its totient is φ = 543120432.

The previous prime is 543120421. The next prime is 543120443. The reversal of 543120433 is 334021345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 377019889 + 166100544 = 19417^2 + 12888^2 .

It is a cyclic number.

It is not a de Polignac number, because 543120433 - 2²⁹ = 6249521 is a prime.

It is a super-3 number, since 3×543120433³ (a number of 27 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 543120398 and 543120407.

It is not a weakly prime, because it can be changed into another prime (543120443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271560216 + 271560217.

It is an arithmetic number, because the mean of its divisors is an integer number (271560217).

Almost surely, 2^543120433 is an apocalyptic number.

It is an amenable number.

543120433 is a deficient number, since it is larger than the sum of its proper divisors (1).

543120433 is an equidigital number, since it uses as much as digits as its factorization.

543120433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 543120433 is about 23304.9443895496. The cubic root of 543120433 is about 815.8908211491.

Adding to 543120433 its reverse (334021345), we get a palindrome (877141778).

The spelling of 543120433 in words is "five hundred forty-three million, one hundred twenty thousand, four hundred thirty-three".