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543124994981 is a prime number
BaseRepresentation
bin1111110011101001100…
…01011011101110100101
31220220220022111102221212
413321310301123232211
532344304444314411
61053301433321205
754145100166602
oct7716461335645
91826808442855
10543124994981
1119a37999a518
1289317566205
133c2a776a19a
141c4048536a9
15e1dbb4e68b
hex7e74c5bba5

543124994981 has 2 divisors, whose sum is σ = 543124994982. Its totient is φ = 543124994980.

The previous prime is 543124994963. The next prime is 543124995011. The reversal of 543124994981 is 189499421345.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 447080786881 + 96044208100 = 668641^2 + 309910^2 .

It is a cyclic number.

It is not a de Polignac number, because 543124994981 - 230 = 542051253157 is a prime.

It is a super-2 number, since 2×5431249949812 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 543124994981.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (543124994911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271562497490 + 271562497491.

It is an arithmetic number, because the mean of its divisors is an integer number (271562497491).

Almost surely, 2543124994981 is an apocalyptic number.

It is an amenable number.

543124994981 is a deficient number, since it is larger than the sum of its proper divisors (1).

543124994981 is an equidigital number, since it uses as much as digits as its factorization.

543124994981 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11197440, while the sum is 59.

The spelling of 543124994981 in words is "five hundred forty-three billion, one hundred twenty-four million, nine hundred ninety-four thousand, nine hundred eighty-one".