Base | Representation |
---|---|
bin | 11000101100101101011100… |
… | …00101011101110110101011 |
3 | 21010022020210011121022000222 |
4 | 30112112232011131312223 |
5 | 24104330034211022012 |
6 | 311302540405520255 |
7 | 14303653241555552 |
oct | 1426265605356653 |
9 | 233266704538028 |
10 | 54312782126507 |
11 | 1633aa15640873 |
12 | 6112220a1308b |
13 | 243c89a547478 |
14 | d5aa774dcd99 |
15 | 642c00540972 |
hex | 3165ae15ddab |
54312782126507 has 2 divisors, whose sum is σ = 54312782126508. Its totient is φ = 54312782126506.
The previous prime is 54312782126381. The next prime is 54312782126531. The reversal of 54312782126507 is 70562128721345.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54312782126507 - 214 = 54312782110123 is a prime.
It is not a weakly prime, because it can be changed into another prime (54312782126557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27156391063253 + 27156391063254.
It is an arithmetic number, because the mean of its divisors is an integer number (27156391063254).
Almost surely, 254312782126507 is an apocalyptic number.
54312782126507 is a deficient number, since it is larger than the sum of its proper divisors (1).
54312782126507 is an equidigital number, since it uses as much as digits as its factorization.
54312782126507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5644800, while the sum is 53.
The spelling of 54312782126507 in words is "fifty-four trillion, three hundred twelve billion, seven hundred eighty-two million, one hundred twenty-six thousand, five hundred seven".
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