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5431341308677 is a prime number
BaseRepresentation
bin100111100001001010100…
…1010110101101100000101
3201020020020111212221101021
41033002111022311230011
51202441341333334202
615315042421431141
71100254462251004
oct117022512655405
921206214787337
105431341308677
111804467634a59
1273876926b4b1
13305233936a6b
1414ac42188c3b
1596435893a37
hex4f0952b5b05

5431341308677 has 2 divisors, whose sum is σ = 5431341308678. Its totient is φ = 5431341308676.

The previous prime is 5431341308651. The next prime is 5431341308683. The reversal of 5431341308677 is 7768031431345.

5431341308677 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5371390275876 + 59951032801 = 2317626^2 + 244849^2 .

It is a cyclic number.

It is not a de Polignac number, because 5431341308677 - 227 = 5431207090949 is a prime.

It is a super-2 number, since 2×54313413086772 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5431341308977) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2715670654338 + 2715670654339.

It is an arithmetic number, because the mean of its divisors is an integer number (2715670654339).

Almost surely, 25431341308677 is an apocalyptic number.

It is an amenable number.

5431341308677 is a deficient number, since it is larger than the sum of its proper divisors (1).

5431341308677 is an equidigital number, since it uses as much as digits as its factorization.

5431341308677 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5080320, while the sum is 52.

The spelling of 5431341308677 in words is "five trillion, four hundred thirty-one billion, three hundred forty-one million, three hundred eight thousand, six hundred seventy-seven".