Base | Representation |
---|---|
bin | 1111110011101011011… |
… | …11000001101101111011 |
3 | 1220220221102212202122022 |
4 | 13321311233001231323 |
5 | 32344323113010441 |
6 | 1053303211345055 |
7 | 54145354345613 |
oct | 7716557015573 |
9 | 1826842782568 |
10 | 543141141371 |
11 | 19a388018544 |
12 | 89320a5218b |
13 | 3c2aac0156a |
14 | 1c406a57a43 |
15 | e1dd28d84b |
hex | 7e75bc1b7b |
543141141371 has 2 divisors, whose sum is σ = 543141141372. Its totient is φ = 543141141370.
The previous prime is 543141141341. The next prime is 543141141379. The reversal of 543141141371 is 173141141345.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-543141141371 is a prime.
It is not a weakly prime, because it can be changed into another prime (543141141379) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271570570685 + 271570570686.
It is an arithmetic number, because the mean of its divisors is an integer number (271570570686).
Almost surely, 2543141141371 is an apocalyptic number.
543141141371 is a deficient number, since it is larger than the sum of its proper divisors (1).
543141141371 is an equidigital number, since it uses as much as digits as its factorization.
543141141371 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20160, while the sum is 35.
The spelling of 543141141371 in words is "five hundred forty-three billion, one hundred forty-one million, one hundred forty-one thousand, three hundred seventy-one".
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