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543141141341 is a prime number
BaseRepresentation
bin1111110011101011011…
…11000001101101011101
31220220221102212202121012
413321311233001231131
532344323113010331
61053303211345005
754145354345541
oct7716557015535
91826842782535
10543141141341
1119a388018517
1289320a52165
133c2aac01546
141c406a57a21
15e1dd28d82b
hex7e75bc1b5d

543141141341 has 2 divisors, whose sum is σ = 543141141342. Its totient is φ = 543141141340.

The previous prime is 543141141293. The next prime is 543141141371. The reversal of 543141141341 is 143141141345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 541622402500 + 1518738841 = 735950^2 + 38971^2 .

It is a cyclic number.

It is not a de Polignac number, because 543141141341 - 214 = 543141124957 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 543141141298 and 543141141307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (543141141371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271570570670 + 271570570671.

It is an arithmetic number, because the mean of its divisors is an integer number (271570570671).

Almost surely, 2543141141341 is an apocalyptic number.

It is an amenable number.

543141141341 is a deficient number, since it is larger than the sum of its proper divisors (1).

543141141341 is an equidigital number, since it uses as much as digits as its factorization.

543141141341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11520, while the sum is 32.

Adding to 543141141341 its reverse (143141141345), we get a palindrome (686282282686).

The spelling of 543141141341 in words is "five hundred forty-three billion, one hundred forty-one million, one hundred forty-one thousand, three hundred forty-one".