Base | Representation |
---|---|
bin | 110010100101011000… |
… | …001111010100111111 |
3 | 12012012020202100210002 |
4 | 302211120033110333 |
5 | 1342213413434211 |
6 | 40541313504515 |
7 | 3631646050256 |
oct | 624530172477 |
9 | 165166670702 |
10 | 54314202431 |
11 | 21041a51205 |
12 | a63987213b |
13 | 51777c2828 |
14 | 28b36b379d |
15 | 162d4d203b |
hex | ca560f53f |
54314202431 has 2 divisors, whose sum is σ = 54314202432. Its totient is φ = 54314202430.
The previous prime is 54314202409. The next prime is 54314202443. The reversal of 54314202431 is 13420241345.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54314202431 is a prime.
It is a super-2 number, since 2×543142024312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 54314202394 and 54314202403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54314202461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27157101215 + 27157101216.
It is an arithmetic number, because the mean of its divisors is an integer number (27157101216).
Almost surely, 254314202431 is an apocalyptic number.
54314202431 is a deficient number, since it is larger than the sum of its proper divisors (1).
54314202431 is an equidigital number, since it uses as much as digits as its factorization.
54314202431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 54314202431 its reverse (13420241345), we get a palindrome (67734443776).
The spelling of 54314202431 in words is "fifty-four billion, three hundred fourteen million, two hundred two thousand, four hundred thirty-one".
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