Base | Representation |
---|---|
bin | 100111100001011110111… |
… | …0000010010000111101100 |
3 | 201020021222222010110122121 |
4 | 1033002331300102013230 |
5 | 1202444240141304400 |
6 | 15315234143522324 |
7 | 1100310400661050 |
oct | 117027560220754 |
9 | 21207888113577 |
10 | 5432022213100 |
11 | 1804786a2158a |
12 | 7389192b93a4 |
13 | 305311a1b5a2 |
14 | 14aca8791c60 |
15 | 9647554321a |
hex | 4f0bdc121ec |
5432022213100 has 36 divisors (see below), whose sum is σ = 13471415090224. Its totient is φ = 1862407615680.
The previous prime is 5432022213061. The next prime is 5432022213103. The reversal of 5432022213100 is 13122202345.
It is a super-2 number, since 2×54320222131002 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (5432022213103) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3880015167 + ... + 3880016566.
Almost surely, 25432022213100 is an apocalyptic number.
5432022213100 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5432022213100 is an abundant number, since it is smaller than the sum of its proper divisors (8039392877124).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5432022213100 is a wasteful number, since it uses less digits than its factorization.
5432022213100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7760031754 (or 7760031747 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 5432022213100 its reverse (13122202345), we get a palindrome (5445144415445).
The spelling of 5432022213100 in words is "five trillion, four hundred thirty-two billion, twenty-two million, two hundred thirteen thousand, one hundred".
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