Base | Representation |
---|---|
bin | 11000101100111101111000… |
… | …10111010010000010110011 |
3 | 21010100002120111211122120202 |
4 | 30112132330113102002303 |
5 | 24110001130033043324 |
6 | 311311000500225415 |
7 | 14304415114140011 |
oct | 1426367427220263 |
9 | 233302514748522 |
10 | 54321611612339 |
11 | 163437366591a5 |
12 | 6113a8599b26b |
13 | 24406768953b6 |
14 | d5b2740098b1 |
15 | 64306a7898ae |
hex | 3167bc5d20b3 |
54321611612339 has 2 divisors, whose sum is σ = 54321611612340. Its totient is φ = 54321611612338.
The previous prime is 54321611612309. The next prime is 54321611612347. The reversal of 54321611612339 is 93321611612345.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54321611612339 - 28 = 54321611612083 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54321611612293 and 54321611612302.
It is not a weakly prime, because it can be changed into another prime (54321611612309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27160805806169 + 27160805806170.
It is an arithmetic number, because the mean of its divisors is an integer number (27160805806170).
Almost surely, 254321611612339 is an apocalyptic number.
54321611612339 is a deficient number, since it is larger than the sum of its proper divisors (1).
54321611612339 is an equidigital number, since it uses as much as digits as its factorization.
54321611612339 is an evil number, because the sum of its binary digits is even.
The product of its digits is 699840, while the sum is 47.
The spelling of 54321611612339 in words is "fifty-four trillion, three hundred twenty-one billion, six hundred eleven million, six hundred twelve thousand, three hundred thirty-nine".
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