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543313473541 is a prime number
BaseRepresentation
bin1111110100000000000…
…00011011000000000101
31220221101110011010221021
413322000000123000011
532400201222123131
61053332245151141
754152546220016
oct7720000330005
91827343133837
10543313473541
1119a466323223
128936a6bb4b1
133c30781c267
141c4218b700d
15e1ed47ee11
hex7e8001b005

543313473541 has 2 divisors, whose sum is σ = 543313473542. Its totient is φ = 543313473540.

The previous prime is 543313473427. The next prime is 543313473587. The reversal of 543313473541 is 145374313345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 412490200516 + 130823273025 = 642254^2 + 361695^2 .

It is a cyclic number.

It is not a de Polignac number, because 543313473541 - 221 = 543311376389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (543313473041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271656736770 + 271656736771.

It is an arithmetic number, because the mean of its divisors is an integer number (271656736771).

Almost surely, 2543313473541 is an apocalyptic number.

It is an amenable number.

543313473541 is a deficient number, since it is larger than the sum of its proper divisors (1).

543313473541 is an equidigital number, since it uses as much as digits as its factorization.

543313473541 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 907200, while the sum is 43.

Adding to 543313473541 its reverse (145374313345), we get a palindrome (688687786886).

The spelling of 543313473541 in words is "five hundred forty-three billion, three hundred thirteen million, four hundred seventy-three thousand, five hundred forty-one".