Base | Representation |
---|---|
bin | 11000101101010100111111… |
… | …01000101111100110000100 |
3 | 21010101021120220011021212002 |
4 | 30112222133220233212010 |
5 | 24110202030211134302 |
6 | 311320411322244432 |
7 | 14305334350322165 |
oct | 1426523750574604 |
9 | 233337526137762 |
10 | 54334014552452 |
11 | 16348a20803728 |
12 | 6116367656718 |
13 | 24418a235a80b |
14 | d5bacd35576c |
15 | 64354459ec02 |
hex | 316a9fa2f984 |
54334014552452 has 24 divisors (see below), whose sum is σ = 97706852143320. Its totient is φ = 26418560175360.
The previous prime is 54334014552449. The next prime is 54334014552491. The reversal of 54334014552452 is 25425541043345.
It can be written as a sum of positive squares in 4 ways, for example, as 870776387716 + 53463238164736 = 933154^2 + 7311856^2 .
It is a junction number, because it is equal to n+sod(n) for n = 54334014552397 and 54334014552406.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 98360177 + ... + 98911032.
It is an arithmetic number, because the mean of its divisors is an integer number (4071118839305).
Almost surely, 254334014552452 is an apocalyptic number.
It is an amenable number.
54334014552452 is a deficient number, since it is larger than the sum of its proper divisors (43372837590868).
54334014552452 is a wasteful number, since it uses less digits than its factorization.
54334014552452 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 197273111 (or 197273109 counting only the distinct ones).
The product of its (nonzero) digits is 5760000, while the sum is 47.
Adding to 54334014552452 its reverse (25425541043345), we get a palindrome (79759555595797).
The spelling of 54334014552452 in words is "fifty-four trillion, three hundred thirty-four billion, fourteen million, five hundred fifty-two thousand, four hundred fifty-two".
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