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54336041214101 is a prime number
BaseRepresentation
bin11000101101011000110000…
…11011110110000010010101
321010101110211010200100222122
430112230120123312002111
524110220203022322401
6311321344400505325
714305435516546553
oct1426543033660225
9233343733610878
1054336041214101
1116349870800609
12611683231b245
132441b361ab4aa
14d5bc42590bd3
1564361247c21b
hex316b186f6095

54336041214101 has 2 divisors, whose sum is σ = 54336041214102. Its totient is φ = 54336041214100.

The previous prime is 54336041214083. The next prime is 54336041214107. The reversal of 54336041214101 is 10141214063345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53653061280625 + 682979933476 = 7324825^2 + 826426^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-54336041214101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54336041214107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27168020607050 + 27168020607051.

It is an arithmetic number, because the mean of its divisors is an integer number (27168020607051).

Almost surely, 254336041214101 is an apocalyptic number.

It is an amenable number.

54336041214101 is a deficient number, since it is larger than the sum of its proper divisors (1).

54336041214101 is an equidigital number, since it uses as much as digits as its factorization.

54336041214101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 35.

Adding to 54336041214101 its reverse (10141214063345), we get a palindrome (64477255277446).

The spelling of 54336041214101 in words is "fifty-four trillion, three hundred thirty-six billion, forty-one million, two hundred fourteen thousand, one hundred one".