Base | Representation |
---|---|
bin | 1010000111110001… |
… | …01100000010010000 |
3 | 112000200211210010000 |
4 | 11003320230002100 |
5 | 42112034314300 |
6 | 2255111210000 |
7 | 251441253360 |
oct | 50370540220 |
9 | 15020753100 |
10 | 5433901200 |
11 | 2339328442 |
12 | 1077976900 |
13 | 687a0ca70 |
14 | 39796c9a0 |
15 | 21c0b4c00 |
hex | 143e2c090 |
5433901200 has 1200 divisors, whose sum is σ = 25526005120. Its totient is φ = 1074954240.
The previous prime is 5433901183. The next prime is 5433901211. The reversal of 5433901200 is 21093345.
It is a tau number, because it is divible by the number of its divisors (1200).
It is a super-2 number, since 2×54339012002 = 59054564502722880000, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 56019552 + ... + 56019648.
Almost surely, 25433901200 is an apocalyptic number.
5433901200 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 5433901200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (12763002560).
5433901200 is an abundant number, since it is smaller than the sum of its proper divisors (20092103920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5433901200 is a wasteful number, since it uses less digits than its factorization.
5433901200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 166 (or 146 counting only the distinct ones).
The product of its (nonzero) digits is 3240, while the sum is 27.
The square root of 5433901200 is about 73714.9998304280. Note that the first 3 decimals coincide. The cubic root of 5433901200 is about 1758.0743832754.
Adding to 5433901200 its reverse (21093345), we get a palindrome (5454994545).
The spelling of 5433901200 in words is "five billion, four hundred thirty-three million, nine hundred one thousand, two hundred".
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