Base | Representation |
---|---|
bin | 100111100010100011011… |
… | …1110110100100001100011 |
3 | 201020111221102021220011002 |
4 | 1033011012332310201203 |
5 | 1203013444033041002 |
6 | 15320254425542215 |
7 | 1100421425056316 |
oct | 117050676644143 |
9 | 21214842256132 |
10 | 5434324502627 |
11 | 18057585667a9 |
12 | 73926034496b |
13 | 3055ba9b5897 |
14 | 14b04645897d |
15 | 9655c718002 |
hex | 4f146fb4863 |
5434324502627 has 2 divisors, whose sum is σ = 5434324502628. Its totient is φ = 5434324502626.
The previous prime is 5434324502567. The next prime is 5434324502693. The reversal of 5434324502627 is 7262054234345.
5434324502627 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5434324502627 - 210 = 5434324501603 is a prime.
It is a super-2 number, since 2×54343245026272 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5434320502627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2717162251313 + 2717162251314.
It is an arithmetic number, because the mean of its divisors is an integer number (2717162251314).
Almost surely, 25434324502627 is an apocalyptic number.
5434324502627 is a deficient number, since it is larger than the sum of its proper divisors (1).
5434324502627 is an equidigital number, since it uses as much as digits as its factorization.
5434324502627 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4838400, while the sum is 47.
The spelling of 5434324502627 in words is "five trillion, four hundred thirty-four billion, three hundred twenty-four million, five hundred two thousand, six hundred twenty-seven".
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