Base | Representation |
---|---|
bin | 110010101001111011… |
… | …010010010101010001 |
3 | 12012101120022121111122 |
4 | 302221323102111101 |
5 | 1342342431424031 |
6 | 40553041052025 |
7 | 3633563416223 |
oct | 625173222521 |
9 | 165346277448 |
10 | 54390498641 |
11 | 21081022726 |
12 | a65b327015 |
13 | 518a55710b |
14 | 28bd894413 |
15 | 163505347b |
hex | ca9ed2551 |
54390498641 has 2 divisors, whose sum is σ = 54390498642. Its totient is φ = 54390498640.
The previous prime is 54390498587. The next prime is 54390498653. The reversal of 54390498641 is 14689409345.
54390498641 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31348473025 + 23042025616 = 177055^2 + 151796^2 .
It is a cyclic number.
It is not a de Polignac number, because 54390498641 - 214 = 54390482257 is a prime.
It is not a weakly prime, because it can be changed into another prime (54390498671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27195249320 + 27195249321.
It is an arithmetic number, because the mean of its divisors is an integer number (27195249321).
Almost surely, 254390498641 is an apocalyptic number.
It is an amenable number.
54390498641 is a deficient number, since it is larger than the sum of its proper divisors (1).
54390498641 is an equidigital number, since it uses as much as digits as its factorization.
54390498641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3732480, while the sum is 53.
The spelling of 54390498641 in words is "fifty-four billion, three hundred ninety million, four hundred ninety-eight thousand, six hundred forty-one".
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