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543914113 is a prime number
BaseRepresentation
bin100000011010110…
…111100010000001
31101220110200220011
4200122313202001
52103220222423
6125545544521
716323123301
oct4032674201
91356420804
10543914113
1125a0307a6
121321a5141
13888bc392
1452347601
1532b3eb0d
hex206b7881

543914113 has 2 divisors, whose sum is σ = 543914114. Its totient is φ = 543914112.

The previous prime is 543914081. The next prime is 543914141. The reversal of 543914113 is 311419345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 543262864 + 651249 = 23308^2 + 807^2 .

It is a cyclic number.

It is not a de Polignac number, because 543914113 - 25 = 543914081 is a prime.

It is not a weakly prime, because it can be changed into another prime (543914213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271957056 + 271957057.

It is an arithmetic number, because the mean of its divisors is an integer number (271957057).

Almost surely, 2543914113 is an apocalyptic number.

It is an amenable number.

543914113 is a deficient number, since it is larger than the sum of its proper divisors (1).

543914113 is an equidigital number, since it uses as much as digits as its factorization.

543914113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6480, while the sum is 31.

The square root of 543914113 is about 23321.9663193308. The cubic root of 543914113 is about 816.2880572018.

The spelling of 543914113 in words is "five hundred forty-three million, nine hundred fourteen thousand, one hundred thirteen".