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54401122038533 is a prime number
BaseRepresentation
bin11000101111010001111111…
…00011011111001100000101
321010121200210201201210120112
430113220333203133030011
524112301444220213113
6311411310324442405
714313231342460514
oct1427507743371405
9233550721653515
1054401122038533
111637442817a226
126127375849405
13244800845596a
14d61057b4467b
15645170c9e5a8
hex317a3f8df305

54401122038533 has 2 divisors, whose sum is σ = 54401122038534. Its totient is φ = 54401122038532.

The previous prime is 54401122038511. The next prime is 54401122038617. The reversal of 54401122038533 is 33583022110445.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 34484118693124 + 19917003345409 = 5872318^2 + 4462847^2 .

It is a cyclic number.

It is not a de Polignac number, because 54401122038533 - 26 = 54401122038469 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54401122058533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27200561019266 + 27200561019267.

It is an arithmetic number, because the mean of its divisors is an integer number (27200561019267).

Almost surely, 254401122038533 is an apocalyptic number.

It is an amenable number.

54401122038533 is a deficient number, since it is larger than the sum of its proper divisors (1).

54401122038533 is an equidigital number, since it uses as much as digits as its factorization.

54401122038533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 345600, while the sum is 41.

Adding to 54401122038533 its reverse (33583022110445), we get a palindrome (87984144148978).

The spelling of 54401122038533 in words is "fifty-four trillion, four hundred one billion, one hundred twenty-two million, thirty-eight thousand, five hundred thirty-three".