Base | Representation |
---|---|
bin | 1100111110000… |
… | …1100110111111 |
3 | 10210100212210022 |
4 | 3033201212333 |
5 | 102411321341 |
6 | 5222002355 |
7 | 1230255605 |
oct | 317414677 |
9 | 123325708 |
10 | 54401471 |
11 | 287876a3 |
12 | 162763bb |
13 | b369927 |
14 | 7321875 |
15 | 4b98e4b |
hex | 33e19bf |
54401471 has 2 divisors, whose sum is σ = 54401472. Its totient is φ = 54401470.
The previous prime is 54401461. The next prime is 54401483. The reversal of 54401471 is 17410445.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54401471 - 210 = 54400447 is a prime.
It is a super-3 number, since 3×544014713 (a number of 24 digits) contains 333 as substring.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 54401471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54401401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27200735 + 27200736.
It is an arithmetic number, because the mean of its divisors is an integer number (27200736).
Almost surely, 254401471 is an apocalyptic number.
54401471 is a deficient number, since it is larger than the sum of its proper divisors (1).
54401471 is an equidigital number, since it uses as much as digits as its factorization.
54401471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2240, while the sum is 26.
The square root of 54401471 is about 7375.7352853800. The cubic root of 54401471 is about 378.9107101171.
It can be divided in two parts, 54401 and 471, that added together give a cube (54872 = 383).
The spelling of 54401471 in words is "fifty-four million, four hundred one thousand, four hundred seventy-one".
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