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54402152131 is a prime number
BaseRepresentation
bin110010101010100111…
…101111011011000011
312012102101020200002101
4302222213233123003
51342403422332011
640554134531231
73634064443345
oct625247573303
9165371220071
1054402152131
1121087662108
12a663206b17
13518caa7482
1428c1249295
1516360a62c1
hexcaa9ef6c3

54402152131 has 2 divisors, whose sum is σ = 54402152132. Its totient is φ = 54402152130.

The previous prime is 54402152083. The next prime is 54402152159. The reversal of 54402152131 is 13125120445.

It is an a-pointer prime, because the next prime (54402152159) can be obtained adding 54402152131 to its sum of digits (28).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 54402152131 - 215 = 54402119363 is a prime.

It is a super-2 number, since 2×544021521312 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 54402152131.

It is not a weakly prime, because it can be changed into another prime (54402152171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27201076065 + 27201076066.

It is an arithmetic number, because the mean of its divisors is an integer number (27201076066).

Almost surely, 254402152131 is an apocalyptic number.

54402152131 is a deficient number, since it is larger than the sum of its proper divisors (1).

54402152131 is an equidigital number, since it uses as much as digits as its factorization.

54402152131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 54402152131 its reverse (13125120445), we get a palindrome (67527272576).

The spelling of 54402152131 in words is "fifty-four billion, four hundred two million, one hundred fifty-two thousand, one hundred thirty-one".