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54403233230453 is a prime number
BaseRepresentation
bin11000101111010101111010…
…11001000010111001110101
321010121220020212022110102212
430113222331121002321311
524112320310201333303
6311412300022543205
714313334556350142
oct1427527531027165
9233556225273385
1054403233230453
1116375310961a38
126127864897b05
132448283961a53
14d611b82a53c9
156452462c7ad8
hex317abd642e75

54403233230453 has 2 divisors, whose sum is σ = 54403233230454. Its totient is φ = 54403233230452.

The previous prime is 54403233230393. The next prime is 54403233230461. The reversal of 54403233230453 is 35403233230445.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49580215507684 + 4823017722769 = 7041322^2 + 2196137^2 .

It is a cyclic number.

It is not a de Polignac number, because 54403233230453 - 224 = 54403216453237 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 54403233230453.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54403233230483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27201616615226 + 27201616615227.

It is an arithmetic number, because the mean of its divisors is an integer number (27201616615227).

Almost surely, 254403233230453 is an apocalyptic number.

It is an amenable number.

54403233230453 is a deficient number, since it is larger than the sum of its proper divisors (1).

54403233230453 is an equidigital number, since it uses as much as digits as its factorization.

54403233230453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1555200, while the sum is 41.

Adding to 54403233230453 its reverse (35403233230445), we get a palindrome (89806466460898).

The spelling of 54403233230453 in words is "fifty-four trillion, four hundred three billion, two hundred thirty-three million, two hundred thirty thousand, four hundred fifty-three".