Base | Representation |
---|---|
bin | 11000101111100010100110… |
… | …10110101010000100000101 |
3 | 21010122112211112021020020212 |
4 | 30113301103112222010011 |
5 | 24112423232300412432 |
6 | 311415343524405205 |
7 | 14313665421266351 |
oct | 1427612326520405 |
9 | 233575745236225 |
10 | 54410044154117 |
11 | 16378196504773 |
12 | 6129045846805 |
13 | 2448acaa367b2 |
14 | d61662a84461 |
15 | 6454e41e42b2 |
hex | 317c535aa105 |
54410044154117 has 2 divisors, whose sum is σ = 54410044154118. Its totient is φ = 54410044154116.
The previous prime is 54410044154071. The next prime is 54410044154159. The reversal of 54410044154117 is 71145144001445.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 37060894870756 + 17349149283361 = 6087766^2 + 4165231^2 .
It is a cyclic number.
It is not a de Polignac number, because 54410044154117 - 210 = 54410044153093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54410044154177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27205022077058 + 27205022077059.
It is an arithmetic number, because the mean of its divisors is an integer number (27205022077059).
Almost surely, 254410044154117 is an apocalyptic number.
It is an amenable number.
54410044154117 is a deficient number, since it is larger than the sum of its proper divisors (1).
54410044154117 is an equidigital number, since it uses as much as digits as its factorization.
54410044154117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 179200, while the sum is 41.
The spelling of 54410044154117 in words is "fifty-four trillion, four hundred ten billion, forty-four million, one hundred fifty-four thousand, one hundred seventeen".
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