Base | Representation |
---|---|
bin | 111101110111001000111111… |
… | …1011101111010100010011011 |
3 | 2122100122021210121022210002001 |
4 | 1323232101333131322202123 |
5 | 1032310142444103310321 |
6 | 5205142305512021431 |
7 | 222420553544626465 |
oct | 17356217735724233 |
9 | 2570567717283061 |
10 | 544140135213211 |
11 | 14841a5986952a9 |
12 | 51042006391877 |
13 | 1a48126b63b484 |
14 | 985274741d135 |
15 | 42d9501104c91 |
hex | 1eee47f77a89b |
544140135213211 has 2 divisors, whose sum is σ = 544140135213212. Its totient is φ = 544140135213210.
The previous prime is 544140135213203. The next prime is 544140135213221. The reversal of 544140135213211 is 112312531041445.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 544140135213211 - 23 = 544140135213203 is a prime.
It is not a weakly prime, because it can be changed into another prime (544140135213221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272070067606605 + 272070067606606.
It is an arithmetic number, because the mean of its divisors is an integer number (272070067606606).
Almost surely, 2544140135213211 is an apocalyptic number.
544140135213211 is a deficient number, since it is larger than the sum of its proper divisors (1).
544140135213211 is an equidigital number, since it uses as much as digits as its factorization.
544140135213211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 37.
Adding to 544140135213211 its reverse (112312531041445), we get a palindrome (656452666254656).
The spelling of 544140135213211 in words is "five hundred forty-four trillion, one hundred forty billion, one hundred thirty-five million, two hundred thirteen thousand, two hundred eleven".
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