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5443000447 is a prime number
BaseRepresentation
bin1010001000110110…
…11001100001111111
3112001022222001221011
411010123121201333
542121402003242
62300034220051
7251611511653
oct50433314177
915038861834
105443000447
112343482885
12107aa24627
13689877631
14398c5aa63
1521ccb0d17
hex1446d987f

5443000447 has 2 divisors, whose sum is σ = 5443000448. Its totient is φ = 5443000446.

The previous prime is 5443000391. The next prime is 5443000463. The reversal of 5443000447 is 7440003445.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5443000447 - 215 = 5442967679 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5443009447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2721500223 + 2721500224.

It is an arithmetic number, because the mean of its divisors is an integer number (2721500224).

Almost surely, 25443000447 is an apocalyptic number.

5443000447 is a deficient number, since it is larger than the sum of its proper divisors (1).

5443000447 is an equidigital number, since it uses as much as digits as its factorization.

5443000447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26880, while the sum is 31.

The square root of 5443000447 is about 73776.6931151024. The cubic root of 5443000447 is about 1759.0551539049.

The spelling of 5443000447 in words is "five billion, four hundred forty-three million, four hundred forty-seven", and thus it is an aban number.