Base | Representation |
---|---|
bin | 1010001000111100… |
… | …00100010110100011 |
3 | 112001101021121201101 |
4 | 11010132010112203 |
5 | 42122041401011 |
6 | 2300101215231 |
7 | 251620454602 |
oct | 50436042643 |
9 | 15041247641 |
10 | 5443700131 |
11 | 2343910531 |
12 | 107b101517 |
13 | 689a60c4c |
14 | 398d9da39 |
15 | 21cd9d2c1 |
hex | 1447845a3 |
5443700131 has 2 divisors, whose sum is σ = 5443700132. Its totient is φ = 5443700130.
The previous prime is 5443700107. The next prime is 5443700159. The reversal of 5443700131 is 1310073445.
It is an a-pointer prime, because the next prime (5443700159) can be obtained adding 5443700131 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5443700131 - 29 = 5443699619 is a prime.
It is a super-2 number, since 2×54437001312 = 59267742232498834322, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5443700131.
It is not a weakly prime, because it can be changed into another prime (5443700231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2721850065 + 2721850066.
It is an arithmetic number, because the mean of its divisors is an integer number (2721850066).
Almost surely, 25443700131 is an apocalyptic number.
5443700131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5443700131 is an equidigital number, since it uses as much as digits as its factorization.
5443700131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 28.
The square root of 5443700131 is about 73781.4348667739. The cubic root of 5443700131 is about 1759.1305247121.
Adding to 5443700131 its reverse (1310073445), we get a palindrome (6753773576).
The spelling of 5443700131 in words is "five billion, four hundred forty-three million, seven hundred thousand, one hundred thirty-one".
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