Base | Representation |
---|---|
bin | 100111100111001111111… |
… | …0010000001010101001111 |
3 | 201021110221220010022122011 |
4 | 1033032133302001111033 |
5 | 1203200114442112111 |
6 | 15325042542002051 |
7 | 1101226261410541 |
oct | 117163762012517 |
9 | 21243856108564 |
10 | 5444404254031 |
11 | 1809a602a2166 |
12 | 73b1b3b76327 |
13 | 306536077222 |
14 | 14b72101b691 |
15 | 9694c5cb021 |
hex | 4f39fc8154f |
5444404254031 has 2 divisors, whose sum is σ = 5444404254032. Its totient is φ = 5444404254030.
The previous prime is 5444404254011. The next prime is 5444404254043. The reversal of 5444404254031 is 1304524044445.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5444404254031 - 25 = 5444404253999 is a prime.
It is a super-2 number, since 2×54444042540312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5444404254011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2722202127015 + 2722202127016.
It is an arithmetic number, because the mean of its divisors is an integer number (2722202127016).
Almost surely, 25444404254031 is an apocalyptic number.
5444404254031 is a deficient number, since it is larger than the sum of its proper divisors (1).
5444404254031 is an equidigital number, since it uses as much as digits as its factorization.
5444404254031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 614400, while the sum is 40.
Adding to 5444404254031 its reverse (1304524044445), we get a palindrome (6748928298476).
The spelling of 5444404254031 in words is "five trillion, four hundred forty-four billion, four hundred four million, two hundred fifty-four thousand, thirty-one".
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