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5444404254493 is a prime number
BaseRepresentation
bin100111100111001111111…
…0010000001011100011101
3201021110221220010100021021
41033032133302001130131
51203200114442120433
615325042542004141
71101226261412101
oct117163762013435
921243856110237
105444404254493
111809a602a2546
1273b1b3b76651
133065360774b9
1414b72101b901
159694c5cb22d
hex4f39fc8171d

5444404254493 has 2 divisors, whose sum is σ = 5444404254494. Its totient is φ = 5444404254492.

The previous prime is 5444404254437. The next prime is 5444404254587. The reversal of 5444404254493 is 3944524044445.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2959373600089 + 2485030654404 = 1720283^2 + 1576398^2 .

It is a cyclic number.

It is not a de Polignac number, because 5444404254493 - 237 = 5306965301021 is a prime.

It is a super-2 number, since 2×54444042544932 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5444404254493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5444404252493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2722202127246 + 2722202127247.

It is an arithmetic number, because the mean of its divisors is an integer number (2722202127247).

Almost surely, 25444404254493 is an apocalyptic number.

It is an amenable number.

5444404254493 is a deficient number, since it is larger than the sum of its proper divisors (1).

5444404254493 is an equidigital number, since it uses as much as digits as its factorization.

5444404254493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 22118400, while the sum is 52.

The spelling of 5444404254493 in words is "five trillion, four hundred forty-four billion, four hundred four million, two hundred fifty-four thousand, four hundred ninety-three".