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544536340141 is a prime number
BaseRepresentation
bin1111110110010001110…
…01010010011010101101
31221001112200012012112211
413323020321102122231
532410202300341031
61054053451330421
754225055343533
oct7731071223255
91831480165484
10544536340141
1119aa33627a82
1289650150a11
133c470c8b871
141c4da07a153
15e2709d5bb1
hex7ec8e526ad

544536340141 has 2 divisors, whose sum is σ = 544536340142. Its totient is φ = 544536340140.

The previous prime is 544536340099. The next prime is 544536340147. The reversal of 544536340141 is 141043635445.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 462026075625 + 82510264516 = 679725^2 + 287246^2 .

It is a cyclic number.

It is not a de Polignac number, because 544536340141 - 29 = 544536339629 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 544536340094 and 544536340103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (544536340147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272268170070 + 272268170071.

It is an arithmetic number, because the mean of its divisors is an integer number (272268170071).

Almost surely, 2544536340141 is an apocalyptic number.

It is an amenable number.

544536340141 is a deficient number, since it is larger than the sum of its proper divisors (1).

544536340141 is an equidigital number, since it uses as much as digits as its factorization.

544536340141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 345600, while the sum is 40.

Adding to 544536340141 its reverse (141043635445), we get a palindrome (685579975586).

The spelling of 544536340141 in words is "five hundred forty-four billion, five hundred thirty-six million, three hundred forty thousand, one hundred forty-one".