Base | Representation |
---|---|
bin | 100111100111110001100… |
… | …0011111110101101111111 |
3 | 201021120212120010100120012 |
4 | 1033033203003332231333 |
5 | 1203204422424113031 |
6 | 15325350543413435 |
7 | 1101266246035361 |
oct | 117174303765577 |
9 | 21246776110505 |
10 | 5445533035391 |
11 | 180a48a485319 |
12 | 73b469bb427b |
13 | 306685b942a7 |
14 | 14b7cacccd31 |
15 | 969b6749b2b |
hex | 4f3e30feb7f |
5445533035391 has 2 divisors, whose sum is σ = 5445533035392. Its totient is φ = 5445533035390.
The previous prime is 5445533035363. The next prime is 5445533035469. The reversal of 5445533035391 is 1935303355445.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5445533035391 is a prime.
It is a super-3 number, since 3×54455330353913 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5445533035301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2722766517695 + 2722766517696.
It is an arithmetic number, because the mean of its divisors is an integer number (2722766517696).
Almost surely, 25445533035391 is an apocalyptic number.
5445533035391 is a deficient number, since it is larger than the sum of its proper divisors (1).
5445533035391 is an equidigital number, since it uses as much as digits as its factorization.
5445533035391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7290000, while the sum is 50.
The spelling of 5445533035391 in words is "five trillion, four hundred forty-five billion, five hundred thirty-three million, thirty-five thousand, three hundred ninety-one".
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