Base | Representation |
---|---|
bin | 110010101110101001… |
… | …011110000110011101 |
3 | 12012121002101012000011 |
4 | 302232221132012131 |
5 | 1343023221324313 |
6 | 41004551003221 |
7 | 3635544634606 |
oct | 625651360635 |
9 | 165532335004 |
10 | 54469714333 |
11 | 21111808641 |
12 | a681969511 |
13 | 51a0aa14c8 |
14 | 28ca1d4dad |
15 | 163be9e93d |
hex | caea5e19d |
54469714333 has 2 divisors, whose sum is σ = 54469714334. Its totient is φ = 54469714332.
The previous prime is 54469714283. The next prime is 54469714363. The reversal of 54469714333 is 33341796445.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 48126706884 + 6343007449 = 219378^2 + 79643^2 .
It is a cyclic number.
It is not a de Polignac number, because 54469714333 - 229 = 53932843421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54469714363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27234857166 + 27234857167.
It is an arithmetic number, because the mean of its divisors is an integer number (27234857167).
Almost surely, 254469714333 is an apocalyptic number.
It is an amenable number.
54469714333 is a deficient number, since it is larger than the sum of its proper divisors (1).
54469714333 is an equidigital number, since it uses as much as digits as its factorization.
54469714333 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3265920, while the sum is 49.
The spelling of 54469714333 in words is "fifty-four billion, four hundred sixty-nine million, seven hundred fourteen thousand, three hundred thirty-three".
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