Base | Representation |
---|---|
bin | 11000110001101011011100… |
… | …10110011111001011101101 |
3 | 21010220120110121010001012001 |
4 | 30120311232112133023231 |
5 | 24120124212423212123 |
6 | 311513214001412301 |
7 | 14322206130614206 |
oct | 1430655626371355 |
9 | 233816417101161 |
10 | 54483511538413 |
11 | 163a63669769a1 |
12 | 613b32993a091 |
13 | 2452a0863b019 |
14 | d65031da85ad |
15 | 647393e1d0ad |
hex | 318d6e59f2ed |
54483511538413 has 2 divisors, whose sum is σ = 54483511538414. Its totient is φ = 54483511538412.
The previous prime is 54483511538399. The next prime is 54483511538459. The reversal of 54483511538413 is 31483511538445.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 51502180956004 + 2981330582409 = 7176502^2 + 1726653^2 .
It is a cyclic number.
It is not a de Polignac number, because 54483511538413 - 25 = 54483511538381 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54483511538213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27241755769206 + 27241755769207.
It is an arithmetic number, because the mean of its divisors is an integer number (27241755769207).
Almost surely, 254483511538413 is an apocalyptic number.
It is an amenable number.
54483511538413 is a deficient number, since it is larger than the sum of its proper divisors (1).
54483511538413 is an equidigital number, since it uses as much as digits as its factorization.
54483511538413 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13824000, while the sum is 55.
The spelling of 54483511538413 in words is "fifty-four trillion, four hundred eighty-three billion, five hundred eleven million, five hundred thirty-eight thousand, four hundred thirteen".
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