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54483511538413 is a prime number
BaseRepresentation
bin11000110001101011011100…
…10110011111001011101101
321010220120110121010001012001
430120311232112133023231
524120124212423212123
6311513214001412301
714322206130614206
oct1430655626371355
9233816417101161
1054483511538413
11163a63669769a1
12613b32993a091
132452a0863b019
14d65031da85ad
15647393e1d0ad
hex318d6e59f2ed

54483511538413 has 2 divisors, whose sum is σ = 54483511538414. Its totient is φ = 54483511538412.

The previous prime is 54483511538399. The next prime is 54483511538459. The reversal of 54483511538413 is 31483511538445.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51502180956004 + 2981330582409 = 7176502^2 + 1726653^2 .

It is a cyclic number.

It is not a de Polignac number, because 54483511538413 - 25 = 54483511538381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54483511538213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27241755769206 + 27241755769207.

It is an arithmetic number, because the mean of its divisors is an integer number (27241755769207).

Almost surely, 254483511538413 is an apocalyptic number.

It is an amenable number.

54483511538413 is a deficient number, since it is larger than the sum of its proper divisors (1).

54483511538413 is an equidigital number, since it uses as much as digits as its factorization.

54483511538413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13824000, while the sum is 55.

The spelling of 54483511538413 in words is "fifty-four trillion, four hundred eighty-three billion, five hundred eleven million, five hundred thirty-eight thousand, four hundred thirteen".