Base | Representation |
---|---|
bin | 100000011111011… |
… | …000011011011001 |
3 | 1101222200211002211 |
4 | 200133120123121 |
5 | 2104021104213 |
6 | 130031155121 |
7 | 16336152226 |
oct | 4037303331 |
9 | 1358624084 |
10 | 545097433 |
11 | 25a769851 |
12 | 132675aa1 |
13 | 88c14b7a |
14 | 5257494d |
15 | 32cc553d |
hex | 207d86d9 |
545097433 has 2 divisors, whose sum is σ = 545097434. Its totient is φ = 545097432.
The previous prime is 545097391. The next prime is 545097439. The reversal of 545097433 is 334790545.
It is a happy number.
545097433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 350550729 + 194546704 = 18723^2 + 13948^2 .
It is a cyclic number.
It is not a de Polignac number, because 545097433 - 29 = 545096921 is a prime.
It is a super-3 number, since 3×5450974333 (a number of 27 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (545097439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272548716 + 272548717.
It is an arithmetic number, because the mean of its divisors is an integer number (272548717).
Almost surely, 2545097433 is an apocalyptic number.
It is an amenable number.
545097433 is a deficient number, since it is larger than the sum of its proper divisors (1).
545097433 is an equidigital number, since it uses as much as digits as its factorization.
545097433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 226800, while the sum is 40.
The square root of 545097433 is about 23347.3217521839. The cubic root of 545097433 is about 816.8795907579.
The spelling of 545097433 in words is "five hundred forty-five million, ninety-seven thousand, four hundred thirty-three".
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