Base | Representation |
---|---|
bin | 11000110010110101110101… |
… | …11100101111010101110111 |
3 | 21011001101120001220012012021 |
4 | 30121122322330233111313 |
5 | 24121303012020341101 |
6 | 311543421110134011 |
7 | 14325121644413653 |
oct | 1431327274572567 |
9 | 234041501805167 |
10 | 54523451340151 |
11 | 164112a1949102 |
12 | 6147015651307 |
13 | 24567020a42c1 |
14 | d66d40585a63 |
15 | 6484304b35a1 |
hex | 3196baf2f577 |
54523451340151 has 2 divisors, whose sum is σ = 54523451340152. Its totient is φ = 54523451340150.
The previous prime is 54523451340139. The next prime is 54523451340181. The reversal of 54523451340151 is 15104315432545.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54523451340151 - 25 = 54523451340119 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54523451340098 and 54523451340107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54523451340131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27261725670075 + 27261725670076.
It is an arithmetic number, because the mean of its divisors is an integer number (27261725670076).
Almost surely, 254523451340151 is an apocalyptic number.
54523451340151 is a deficient number, since it is larger than the sum of its proper divisors (1).
54523451340151 is an equidigital number, since it uses as much as digits as its factorization.
54523451340151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720000, while the sum is 43.
Adding to 54523451340151 its reverse (15104315432545), we get a palindrome (69627766772696).
The spelling of 54523451340151 in words is "fifty-four trillion, five hundred twenty-three billion, four hundred fifty-one million, three hundred forty thousand, one hundred fifty-one".
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