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54523451340151 is a prime number
BaseRepresentation
bin11000110010110101110101…
…11100101111010101110111
321011001101120001220012012021
430121122322330233111313
524121303012020341101
6311543421110134011
714325121644413653
oct1431327274572567
9234041501805167
1054523451340151
11164112a1949102
126147015651307
1324567020a42c1
14d66d40585a63
156484304b35a1
hex3196baf2f577

54523451340151 has 2 divisors, whose sum is σ = 54523451340152. Its totient is φ = 54523451340150.

The previous prime is 54523451340139. The next prime is 54523451340181. The reversal of 54523451340151 is 15104315432545.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 54523451340151 - 25 = 54523451340119 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 54523451340098 and 54523451340107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54523451340131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27261725670075 + 27261725670076.

It is an arithmetic number, because the mean of its divisors is an integer number (27261725670076).

Almost surely, 254523451340151 is an apocalyptic number.

54523451340151 is a deficient number, since it is larger than the sum of its proper divisors (1).

54523451340151 is an equidigital number, since it uses as much as digits as its factorization.

54523451340151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720000, while the sum is 43.

Adding to 54523451340151 its reverse (15104315432545), we get a palindrome (69627766772696).

The spelling of 54523451340151 in words is "fifty-four trillion, five hundred twenty-three billion, four hundred fifty-one million, three hundred forty thousand, one hundred fifty-one".