Base | Representation |
---|---|
bin | 1111110111101101001… |
… | …01111110110101011101 |
3 | 1221010112002212010212111 |
4 | 13323312211332311131 |
5 | 32413240033444013 |
6 | 1054301520234021 |
7 | 54253055200330 |
oct | 7736645766535 |
9 | 1833462763774 |
10 | 545303031133 |
11 | 1a02973882a3 |
12 | 89824a6b911 |
13 | 3c563a7b583 |
14 | 1c56dc14617 |
15 | e2b7e7d73d |
hex | 7ef697ed5d |
545303031133 has 32 divisors (see below), whose sum is σ = 640641710592. Its totient is φ = 454519296000.
The previous prime is 545303031131. The next prime is 545303031151. The reversal of 545303031133 is 331130303545.
It is not a de Polignac number, because 545303031133 - 21 = 545303031131 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 545303031095 and 545303031104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (545303031131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 19334560 + ... + 19362742.
It is an arithmetic number, because the mean of its divisors is an integer number (20020053456).
Almost surely, 2545303031133 is an apocalyptic number.
It is an amenable number.
545303031133 is a deficient number, since it is larger than the sum of its proper divisors (95338679459).
545303031133 is a wasteful number, since it uses less digits than its factorization.
545303031133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28765.
The product of its (nonzero) digits is 24300, while the sum is 31.
Adding to 545303031133 its reverse (331130303545), we get a palindrome (876433334678).
The spelling of 545303031133 in words is "five hundred forty-five billion, three hundred three million, thirty-one thousand, one hundred thirty-three".
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