Base | Representation |
---|---|
bin | 110010110010111001… |
… | …111001101001100101 |
3 | 12012210001202111100111 |
4 | 302302321321221211 |
5 | 1343200012132331 |
6 | 41020021413021 |
7 | 3640402646545 |
oct | 626271715145 |
9 | 165701674314 |
10 | 54541130341 |
11 | 21149056535 |
12 | a6a186a171 |
13 | 51b28176b9 |
14 | 28d58a5325 |
15 | 16433a9db1 |
hex | cb2e79a65 |
54541130341 has 2 divisors, whose sum is σ = 54541130342. Its totient is φ = 54541130340.
The previous prime is 54541130323. The next prime is 54541130407. The reversal of 54541130341 is 14303114545.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50512562500 + 4028567841 = 224750^2 + 63471^2 .
It is a cyclic number.
It is not a de Polignac number, because 54541130341 - 25 = 54541130309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54541130741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27270565170 + 27270565171.
It is an arithmetic number, because the mean of its divisors is an integer number (27270565171).
Almost surely, 254541130341 is an apocalyptic number.
It is an amenable number.
54541130341 is a deficient number, since it is larger than the sum of its proper divisors (1).
54541130341 is an equidigital number, since it uses as much as digits as its factorization.
54541130341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 54541130341 its reverse (14303114545), we get a palindrome (68844244886).
The spelling of 54541130341 in words is "fifty-four billion, five hundred forty-one million, one hundred thirty thousand, three hundred forty-one".
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