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545441214533 is a prime number
BaseRepresentation
bin1111110111111101101…
…01000111000001000101
31221010212201212120212012
413323332311013001011
532414030422331113
61054323334104005
754256353553355
oct7737665070105
91833781776765
10545441214533
111a0358389556
12898631ab005
133c5865a0ab7
141c584304b65
15e2c5176aa8
hex7efed47045

545441214533 has 2 divisors, whose sum is σ = 545441214534. Its totient is φ = 545441214532.

The previous prime is 545441214511. The next prime is 545441214569. The reversal of 545441214533 is 335412144545.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 495639936289 + 49801278244 = 704017^2 + 223162^2 .

It is a cyclic number.

It is not a de Polignac number, because 545441214533 - 26 = 545441214469 is a prime.

It is a super-2 number, since 2×5454412145332 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (545441214503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272720607266 + 272720607267.

It is an arithmetic number, because the mean of its divisors is an integer number (272720607267).

Almost surely, 2545441214533 is an apocalyptic number.

It is an amenable number.

545441214533 is a deficient number, since it is larger than the sum of its proper divisors (1).

545441214533 is an equidigital number, since it uses as much as digits as its factorization.

545441214533 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 576000, while the sum is 41.

The spelling of 545441214533 in words is "five hundred forty-five billion, four hundred forty-one million, two hundred fourteen thousand, five hundred thirty-three".