Base | Representation |
---|---|
bin | 100111101100111001101… |
… | …0101011000001110111111 |
3 | 201022122021220011101000121 |
4 | 1033121303111120032333 |
5 | 1203400000110400142 |
6 | 15334411303035411 |
7 | 1102136143025554 |
oct | 117316325301677 |
9 | 21278256141017 |
10 | 5456543450047 |
11 | 181411a586868 |
12 | 74162143bb67 |
13 | 30771bcc7151 |
14 | 14c153310a2b |
15 | 96e0d194c67 |
hex | 4f6735583bf |
5456543450047 has 2 divisors, whose sum is σ = 5456543450048. Its totient is φ = 5456543450046.
The previous prime is 5456543449999. The next prime is 5456543450093. The reversal of 5456543450047 is 7400543456545.
5456543450047 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5456543450047 - 239 = 4906787636159 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5456543449976 and 5456543450003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5456543453047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2728271725023 + 2728271725024.
It is an arithmetic number, because the mean of its divisors is an integer number (2728271725024).
Almost surely, 25456543450047 is an apocalyptic number.
5456543450047 is a deficient number, since it is larger than the sum of its proper divisors (1).
5456543450047 is an equidigital number, since it uses as much as digits as its factorization.
5456543450047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160000, while the sum is 52.
The spelling of 5456543450047 in words is "five trillion, four hundred fifty-six billion, five hundred forty-three million, four hundred fifty thousand, forty-seven".
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