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5461624825403 is a prime number
BaseRepresentation
bin100111101111010001000…
…1101010010011000111011
3201100010102000122222120212
41033132202031102120323
51203440401423403103
615341011422341335
71102406104015145
oct117364215223073
921303360588525
105461624825403
11181629791432a
127425bb12a84b
1330804b978126
1414c4b6115c95
15971093227d8
hex4f7a235263b

5461624825403 has 2 divisors, whose sum is σ = 5461624825404. Its totient is φ = 5461624825402.

The previous prime is 5461624825309. The next prime is 5461624825493. The reversal of 5461624825403 is 3045284261645.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5461624825403 - 214 = 5461624809019 is a prime.

It is a super-2 number, since 2×54616248254032 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5461624825493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2730812412701 + 2730812412702.

It is an arithmetic number, because the mean of its divisors is an integer number (2730812412702).

Almost surely, 25461624825403 is an apocalyptic number.

5461624825403 is a deficient number, since it is larger than the sum of its proper divisors (1).

5461624825403 is an equidigital number, since it uses as much as digits as its factorization.

5461624825403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5529600, while the sum is 50.

The spelling of 5461624825403 in words is "five trillion, four hundred sixty-one billion, six hundred twenty-four million, eight hundred twenty-five thousand, four hundred three".