Base | Representation |
---|---|
bin | 100111101111010001000… |
… | …1101010010011010010101 |
3 | 201100010102000122222201012 |
4 | 1033132202031102122111 |
5 | 1203440401423403433 |
6 | 15341011422342005 |
7 | 1102406104015334 |
oct | 117364215223225 |
9 | 21303360588635 |
10 | 5461624825493 |
11 | 1816297914401 |
12 | 7425bb12a905 |
13 | 30804b978195 |
14 | 14c4b6115d1b |
15 | 97109322848 |
hex | 4f7a2352695 |
5461624825493 has 2 divisors, whose sum is σ = 5461624825494. Its totient is φ = 5461624825492.
The previous prime is 5461624825403. The next prime is 5461624825499. The reversal of 5461624825493 is 3945284261645.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5184082352164 + 277542473329 = 2276858^2 + 526823^2 .
It is a cyclic number.
It is not a de Polignac number, because 5461624825493 - 216 = 5461624759957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5461624825499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2730812412746 + 2730812412747.
It is an arithmetic number, because the mean of its divisors is an integer number (2730812412747).
Almost surely, 25461624825493 is an apocalyptic number.
It is an amenable number.
5461624825493 is a deficient number, since it is larger than the sum of its proper divisors (1).
5461624825493 is an equidigital number, since it uses as much as digits as its factorization.
5461624825493 is an evil number, because the sum of its binary digits is even.
The product of its digits is 49766400, while the sum is 59.
The spelling of 5461624825493 in words is "five trillion, four hundred sixty-one billion, six hundred twenty-four million, eight hundred twenty-five thousand, four hundred ninety-three".
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