Base | Representation |
---|---|
bin | 11000110101101101100001… |
… | …10010000100111001010111 |
3 | 21011101211002121221012101211 |
4 | 30122312300302010321113 |
5 | 24124411442121124003 |
6 | 312101010311402251 |
7 | 14335212456025141 |
oct | 1432666062047127 |
9 | 234354077835354 |
10 | 54622065020503 |
11 | 1644a0a6789792 |
12 | 6162157083387 |
13 | 2462ab9615056 |
14 | d6ba17455c91 |
15 | 64aca2b5b96d |
hex | 31adb0c84e57 |
54622065020503 has 2 divisors, whose sum is σ = 54622065020504. Its totient is φ = 54622065020502.
The previous prime is 54622065020489. The next prime is 54622065020561. The reversal of 54622065020503 is 30502056022645.
54622065020503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54622065020503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54622065020903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27311032510251 + 27311032510252.
It is an arithmetic number, because the mean of its divisors is an integer number (27311032510252).
Almost surely, 254622065020503 is an apocalyptic number.
54622065020503 is a deficient number, since it is larger than the sum of its proper divisors (1).
54622065020503 is an equidigital number, since it uses as much as digits as its factorization.
54622065020503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432000, while the sum is 40.
The spelling of 54622065020503 in words is "fifty-four trillion, six hundred twenty-two billion, sixty-five million, twenty thousand, five hundred three".
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