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54630221441 is a prime number
BaseRepresentation
bin110010111000001101…
…110000011010000001
312020000021101210100212
4302320031300122001
51343340314041231
641032523123505
73642534135425
oct627015603201
9166007353325
1054630221441
1121194376a44
12a707673595
1351c810ba23
142903656b85
15164b10742b
hexcb8370681

54630221441 has 2 divisors, whose sum is σ = 54630221442. Its totient is φ = 54630221440.

The previous prime is 54630221351. The next prime is 54630221467. The reversal of 54630221441 is 14412203645.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43520218225 + 11110003216 = 208615^2 + 105404^2 .

It is a cyclic number.

It is not a de Polignac number, because 54630221441 - 210 = 54630220417 is a prime.

It is a super-3 number, since 3×546302214413 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 54630221398 and 54630221407.

It is not a weakly prime, because it can be changed into another prime (54630221491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27315110720 + 27315110721.

It is an arithmetic number, because the mean of its divisors is an integer number (27315110721).

Almost surely, 254630221441 is an apocalyptic number.

It is an amenable number.

54630221441 is a deficient number, since it is larger than the sum of its proper divisors (1).

54630221441 is an equidigital number, since it uses as much as digits as its factorization.

54630221441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 32.

The spelling of 54630221441 in words is "fifty-four billion, six hundred thirty million, two hundred twenty-one thousand, four hundred forty-one".