Base | Representation |
---|---|
bin | 11000110110101100110011… |
… | …11110001010100111000101 |
3 | 21011112001210112201020102011 |
4 | 30123112121332022213011 |
5 | 24130441033231131122 |
6 | 312124350013214221 |
7 | 14340524450026126 |
oct | 1433263176124705 |
9 | 234461715636364 |
10 | 54656042052037 |
11 | 16462551949438 |
12 | 6168859a91371 |
13 | 246607291923a |
14 | d6d51bb5604d |
15 | 64bae09c0377 |
hex | 31b599f8a9c5 |
54656042052037 has 2 divisors, whose sum is σ = 54656042052038. Its totient is φ = 54656042052036.
The previous prime is 54656042051929. The next prime is 54656042052133. The reversal of 54656042052037 is 73025024065645.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31250436663681 + 23405605388356 = 5590209^2 + 4837934^2 .
It is a cyclic number.
It is not a de Polignac number, because 54656042052037 - 231 = 54653894568389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54656042052137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27328021026018 + 27328021026019.
It is an arithmetic number, because the mean of its divisors is an integer number (27328021026019).
Almost surely, 254656042052037 is an apocalyptic number.
It is an amenable number.
54656042052037 is a deficient number, since it is larger than the sum of its proper divisors (1).
54656042052037 is an equidigital number, since it uses as much as digits as its factorization.
54656042052037 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048000, while the sum is 49.
The spelling of 54656042052037 in words is "fifty-four trillion, six hundred fifty-six billion, forty-two million, fifty-two thousand, thirty-seven".
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