Base | Representation |
---|---|
bin | 110010111001110001… |
… | …101000101101101011 |
3 | 12020002002200000112112 |
4 | 302321301220231223 |
5 | 1343414014414311 |
6 | 41035300232535 |
7 | 3643302525404 |
oct | 627161505553 |
9 | 166062600475 |
10 | 54656404331 |
11 | 211a812a5a1 |
12 | a71439b74b |
13 | 5200678469 |
14 | 2906d109ab |
15 | 164d57a28b |
hex | cb9c68b6b |
54656404331 has 2 divisors, whose sum is σ = 54656404332. Its totient is φ = 54656404330.
The previous prime is 54656404289. The next prime is 54656404333. The reversal of 54656404331 is 13340465645.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54656404331 is a prime.
It is a super-2 number, since 2×546564043312 (a number of 22 digits) contains 22 as substring.
Together with 54656404333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (54656404333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27328202165 + 27328202166.
It is an arithmetic number, because the mean of its divisors is an integer number (27328202166).
Almost surely, 254656404331 is an apocalyptic number.
54656404331 is a deficient number, since it is larger than the sum of its proper divisors (1).
54656404331 is an equidigital number, since it uses as much as digits as its factorization.
54656404331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 41.
Adding to 54656404331 its reverse (13340465645), we get a palindrome (67996869976).
The spelling of 54656404331 in words is "fifty-four billion, six hundred fifty-six million, four hundred four thousand, three hundred thirty-one".
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