Base | Representation |
---|---|
bin | 110010111100100111… |
… | …101001011011001101 |
3 | 12020012102110002122012 |
4 | 302330213221123031 |
5 | 1344013223224303 |
6 | 41044123031005 |
7 | 3644422216616 |
oct | 627447513315 |
9 | 166172402565 |
10 | 54704117453 |
11 | 21222059127 |
12 | a72836b465 |
13 | 520a51298b |
14 | 290d3b0c0d |
15 | 16528525d8 |
hex | cbc9e96cd |
54704117453 has 2 divisors, whose sum is σ = 54704117454. Its totient is φ = 54704117452.
The previous prime is 54704117449. The next prime is 54704117459. The reversal of 54704117453 is 35471140745.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32111923204 + 22592194249 = 179198^2 + 150307^2 .
It is a cyclic number.
It is not a de Polignac number, because 54704117453 - 22 = 54704117449 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 54704117453.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54704117459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27352058726 + 27352058727.
It is an arithmetic number, because the mean of its divisors is an integer number (27352058727).
Almost surely, 254704117453 is an apocalyptic number.
It is an amenable number.
54704117453 is a deficient number, since it is larger than the sum of its proper divisors (1).
54704117453 is an equidigital number, since it uses as much as digits as its factorization.
54704117453 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 235200, while the sum is 41.
The spelling of 54704117453 in words is "fifty-four billion, seven hundred four million, one hundred seventeen thousand, four hundred fifty-three".
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