Base | Representation |
---|---|
bin | 110010111101001111… |
… | …010011100000000001 |
3 | 12020020011000021012121 |
4 | 302331033103200001 |
5 | 1344023403412114 |
6 | 41045133524241 |
7 | 3644606455543 |
oct | 627517234001 |
9 | 166204007177 |
10 | 54714513409 |
11 | 21227a09826 |
12 | a72b943681 |
13 | 520c71282a |
14 | 2910919693 |
15 | 1653707a24 |
hex | cbd3d3801 |
54714513409 has 2 divisors, whose sum is σ = 54714513410. Its totient is φ = 54714513408.
The previous prime is 54714513397. The next prime is 54714513419. The reversal of 54714513409 is 90431541745.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 39362560000 + 15351953409 = 198400^2 + 123903^2 .
It is a cyclic number.
It is not a de Polignac number, because 54714513409 - 27 = 54714513281 is a prime.
It is not a weakly prime, because it can be changed into another prime (54714513419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27357256704 + 27357256705.
It is an arithmetic number, because the mean of its divisors is an integer number (27357256705).
Almost surely, 254714513409 is an apocalyptic number.
It is an amenable number.
54714513409 is a deficient number, since it is larger than the sum of its proper divisors (1).
54714513409 is an equidigital number, since it uses as much as digits as its factorization.
54714513409 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 302400, while the sum is 43.
The spelling of 54714513409 in words is "fifty-four billion, seven hundred fourteen million, five hundred thirteen thousand, four hundred nine".
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