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54714829895333 is a prime number
BaseRepresentation
bin11000111000011010010011…
…11111111111011010100101
321011201200112120102002202122
430130031021333333122211
524132421432423122313
6312211351300515325
714345005330324226
oct1434151177773245
9234650476362678
1054714829895333
111648547a0771a3
1261781259abb45
13246b7811b682a
14d722d763324d
1564d3d1ad5708
hex31c349fff6a5

54714829895333 has 2 divisors, whose sum is σ = 54714829895334. Its totient is φ = 54714829895332.

The previous prime is 54714829895311. The next prime is 54714829895371. The reversal of 54714829895333 is 33359892841745.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51761938208929 + 2952891686404 = 7194577^2 + 1718398^2 .

It is a cyclic number.

It is not a de Polignac number, because 54714829895333 - 214 = 54714829878949 is a prime.

It is a super-2 number, since 2×547148298953332 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54714829895303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27357414947666 + 27357414947667.

It is an arithmetic number, because the mean of its divisors is an integer number (27357414947667).

Almost surely, 254714829895333 is an apocalyptic number.

It is an amenable number.

54714829895333 is a deficient number, since it is larger than the sum of its proper divisors (1).

54714829895333 is an equidigital number, since it uses as much as digits as its factorization.

54714829895333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 783820800, while the sum is 71.

The spelling of 54714829895333 in words is "fifty-four trillion, seven hundred fourteen billion, eight hundred twenty-nine million, eight hundred ninety-five thousand, three hundred thirty-three".