Base | Representation |
---|---|
bin | 1010001100111010… |
… | …00100010110010001 |
3 | 112010200221001010102 |
4 | 11012131010112101 |
5 | 42204102224101 |
6 | 2303250542145 |
7 | 252503444606 |
oct | 50635042621 |
9 | 15120831112 |
10 | 5476992401 |
11 | 236068a501 |
12 | 108a297955 |
13 | 69391960a |
14 | 39d5886ad |
15 | 220c7786b |
hex | 146744591 |
5476992401 has 2 divisors, whose sum is σ = 5476992402. Its totient is φ = 5476992400.
The previous prime is 5476992373. The next prime is 5476992419. The reversal of 5476992401 is 1042996745.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4786564225 + 690428176 = 69185^2 + 26276^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5476992401 is a prime.
It is a super-2 number, since 2×54769924012 = 59994891521223489602, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5476992481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2738496200 + 2738496201.
It is an arithmetic number, because the mean of its divisors is an integer number (2738496201).
Almost surely, 25476992401 is an apocalyptic number.
It is an amenable number.
5476992401 is a deficient number, since it is larger than the sum of its proper divisors (1).
5476992401 is an equidigital number, since it uses as much as digits as its factorization.
5476992401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 47.
The square root of 5476992401 is about 74006.7051083887. The cubic root of 5476992401 is about 1762.7093687936.
The spelling of 5476992401 in words is "five billion, four hundred seventy-six million, nine hundred ninety-two thousand, four hundred one".
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