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54771131 is a prime number
BaseRepresentation
bin1101000011101…
…1110110111011
310211001122212102
43100323312323
5103010134011
65233534015
71233355412
oct320736673
9124048772
1054771131
1128a0a3a8
121641430b
13b468c6c
1473ba479
154c1d73b
hex343bdbb

54771131 has 2 divisors, whose sum is σ = 54771132. Its totient is φ = 54771130.

The previous prime is 54771113. The next prime is 54771133. The reversal of 54771131 is 13117745.

Together with previous prime (54771113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 54771131 - 214 = 54754747 is a prime.

It is a super-2 number, since 2×547711312 = 5999753582038322, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 54771133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 54771094 and 54771103.

It is not a weakly prime, because it can be changed into another prime (54771133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27385565 + 27385566.

It is an arithmetic number, because the mean of its divisors is an integer number (27385566).

Almost surely, 254771131 is an apocalyptic number.

54771131 is a deficient number, since it is larger than the sum of its proper divisors (1).

54771131 is an equidigital number, since it uses as much as digits as its factorization.

54771131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2940, while the sum is 29.

The square root of 54771131 is about 7400.7520563791. The cubic root of 54771131 is about 379.7670109164.

Adding to 54771131 its reverse (13117745), we get a palindrome (67888876).

The spelling of 54771131 in words is "fifty-four million, seven hundred seventy-one thousand, one hundred thirty-one".